decimal=decimal+bit*1;//add it, multiplied by the corresponding power of 2 binary=binary/10;//get rid of the 6th bit, now the 5th bit is last bit=binary%10;//get the last bit (5th) decimal=decimal+bit ...

* 1*2^6+1*2^5+0*2^4+0*2^3+1*2^2+0*2^1+0*2^0 int mod = binary%10;//1100100%10=0,110010%10=0,11001%10=1,1100%10=0,110%10=0,11%10=1,1%10=1 decimal = decimal+(mod*(int ...